Disable shellcheck in usplit

The local variables aren't picked up by shellcheck because of the printf level
of indirection I do later in the function, which is the reason /why/ I use a
variable in the first argument to printf.

1 files changed, 8 insertions, 5 deletions

@@ -223,11 +223,12 @@ usplit() { # usplit NAME:ARRAY URL:STRING
         local re='^(([^:/?#]+):)?(//([^/?#]*))?([^?#]*)(\?([^#]*))?(#(.*))?'
         [[ $2 =~ $re ]] || return $?
 
-        local scheme="${BASH_REMATCH[2]}"
-        local authority="${BASH_REMATCH[4]}"
-        local path="${BASH_REMATCH[5]}"
-        local query="${BASH_REMATCH[7]}"
-        local fragment="${BASH_REMATCH[9]}"
+        # shellcheck disable=2034
+        local scheme="${BASH_REMATCH[2]}" \
+                authority="${BASH_REMATCH[4]}" \
+                path="${BASH_REMATCH[5]}" \
+                query="${BASH_REMATCH[7]}" \
+                fragment="${BASH_REMATCH[9]}"
 
         # 0=url 1=scheme 2=authority 3=path 4=query 5=fragment
         local i=1 c
@@ -235,10 +236,12 @@ usplit() { # usplit NAME:ARRAY URL:STRING
                 if [[ "${!c}" || "$c" == path ]]; then
                         printf -v "$1[$i]" '%s' "${!c}"
                 else
+                        # shellcheck disable=2059
                         printf -v "$1[$i]" "$UC_BLANK"
                 fi
                 ((i += 1))
         done
+        # shellcheck disable=2059
         printf -v "$1[0]" "$(ujoin "$1")" # inefficient I'm sure
 }